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5^2+12r=-4r^2-4
We move all terms to the left:
5^2+12r-(-4r^2-4)=0
We add all the numbers together, and all the variables
-(-4r^2-4)+12r+25=0
We get rid of parentheses
4r^2+12r+4+25=0
We add all the numbers together, and all the variables
4r^2+12r+29=0
a = 4; b = 12; c = +29;
Δ = b2-4ac
Δ = 122-4·4·29
Δ = -320
Delta is less than zero, so there is no solution for the equation
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